We need the law of sines to solve for triangles that are not 90* triangles. With the triangle having sides a, b and c, and angles A, B and C, C can be cut down to make 2 90* triangles. Using opposite over hypotenuse, the trig functions are rearranged. When everything is then equal to height, and everything is simplified, the law of sines is done.
4. Area formulas - How is the “area of an oblique” triangle derived? How does it relate to the area formula that you are familiar with?
The area is derived from the original a=(b)(h) but the change is that instead of all 3 sides given, only 2 sides are given, with 1 angle (SAS). There are 3 given formulas we can use, depending on what information is given to us, but it is just a matter of manipulating the formula to get what we need.
| |||||
| |||||
|
REFRENCES:
http://math.ucsd.edu/~wgarner/math4c/derivations/trigidentities/lawofsines.htm
http://www.mathsisfun.com/algebra/trig-area-triangle-without-right-angle.html
No comments:
Post a Comment