SV#1: Unit F Concept 10 - Finding all real and imaginary zeroes of a polynomial

This problem is about finding real and complex numbers. Here, we find out how to find the zeros of an equation. The zeros can be real or imaginary, here's an example of imaginary zeros.



Pay special attention to how I plug in the zeros to the calculator. Also, pay special attention to my final answer because it can be written 2 different ways. Other than that, I explain every step of the way. :)
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WPP#4: Unit E Concept 3 - Maximizing Area

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SP#2: Unit E Concept 7 - Graphing a polynomial and identifying all key parts

This problem is about graphing polynomails, including the x and y intercept (with multiplicities), end behavior. 

To begin with, I factored out the equation above which lead me to my zeros. My original equation was to the 4th power which means I need 4 zeros. When i factored out the equation, I ended up with 4 zeros. Also, since the original equation started with "x^4" (both positive = even positive) the graph will be going up whether it's going to infnity or negative infinity. We find the y-intercept by setting "x" to 0 in the original equation. After all that, we plot all the points given, and make sure the graph is going upwards both ways. :)

SP#1: Unit E Concept 1 - Graphing a quadratic and identifying all key parts

This problem is about identifying x-intercepts, y intercepts, the vertex, the axis of quadratics and how to graph it. Here's an example where I used my own example. 

To begin with, my problem was f(x)=2x^2+4x-16. I subtracted 16 on both sides which gave me 2x^2+4x=16. I then took out the coeficiant which is 2 and added it to the other side as well, and it gave me 2(x^2+2x)=16+2. After, I divided "b" by 2 which is 1 and squared it which is 1 and added 1 to both sides. I ended up with 2(x^2+2x+1)= 16+2(1). KEEP IN MIND THAT "2(x^2+2x+1)" FACTORS OUT. 2(x+1)^2=18. Subtract 18 over and we have the parent function equation which is 2(x+1)^2-18. The vertex is a minimum and is (-1,-18). To find the y intercept, we would need to set "x"=to 0 in the original equation which makes it (0,-16). The axis is "x=-1" because of the vertex. Now to find the x intercepts, we just need to solve, "2(x+1)^2=18" :)

WPP#3: Unit E Concept 2 - Path of Soccer Ball

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WPP#2: Unit A Concept 7 - Profit, Revenue, Cost

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WPP#1: Unit A Concept 6 - Linear Models

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