In order to fully understand this problem, we must pay attention to the repeating numbers. For example, in this problem, out repeating numbers are 24. We must remember to ignore to 10 (number in front of the decimal) and remember to add it in the end. We must always remember that we can only add fractions together if they have the same denominator. Other than that, the problem should be pretty clear. :) Thanks for viewing. :)
Monday, December 9, 2013
Sunday, December 1, 2013
Fibonacci Beauty Ratio
Friend’ s name
|
Foot to Navel: 97.5 cm
|
Navel to top of head: 62cm
|
Ratio: 1.573cm
|
Average:
|
Alexis
|
Navel to chin: 43cm
|
Chin to top of head: 20cm
|
Ratio: 2.150cm
|
1.562cm
|
Tran
|
Knee to Navel: 50cm
|
Foot to navel: 47cm
|
Ratio: 1.064cm
|
Friend’ s name
|
Foot to Navel: 103cm
|
Navel to top of head: 59cm
|
Ratio: 1.746cm
|
Average:
|
Judith
|
Navel to chin: 41.5cm
|
Chin to top of head: 20cm
|
Ratio: 2.075cm
|
1.649cm
|
Q
|
Knee to Navel: 54cm
|
Foot to navel: 48cm
|
Ratio: 1.125cm
|
Friend’ s name
|
Foot to Navel: 102cm
|
Navel to top of head: 68cm
|
Ratio: 1.5cm
|
Average:
|
Brian
|
Navel to chin: 45cm
|
Chin to top of head: 21cm
|
Ratio: 2.143cm
|
1.582cm
|
C
|
Knee to Navel: 54cm
|
Foot to navel: 49cm
|
Ratio: 1.102cm
|
Friend’ s name
|
Foot to Navel: 97cm
|
Navel to top of head: 59cm
|
Ratio: 1.644cm
|
Average:
|
Janet
|
Navel to chin: 41cm
|
Chin to top of head: 18cm
|
Ratio: 2.278cm
|
1.69cm
|
Garcia
|
Knee to Navel: 53cm
|
Foot to navel: 46cm
|
Ratio: 1.152cm
|
Friend’ s name
|
Foot to Navel: 88cm
|
Navel to top of head: 66cm
|
Ratio: 1.33cm
|
Average:
|
Gloria
|
Navel to chin: 45cm
|
Chin to top of head: 21cm
|
Ratio: 2.143cm
|
1.498cm
|
Garcia
|
Knee to Navel: 47cm
|
Foot to navel: 46cm
|
Ratio: 1.022cm
|
Monday, November 18, 2013
SP #5 Unit J Concept 6 Repeating Factors in Fraction Decomposition
Tuesday, November 12, 2013
SV5: Unit J Concepts 3-4
In order to fully understand this video, you must know how to use the graphing calculator to check answers. I did not completely show every step, only the end. Also, we must know how to back substitute, both of my equations were already given but its not always like that. THANKS FOR WATCHING.
Tuesday, November 5, 2013
WPP # 6, Concept I Unit 3-5
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Sunday, November 3, 2013
SV #4; Unit I Concept 2; Graphing Logarithmic functions and identifying x-intercepts, y-intercepts, asymptote, domain, and range
In order to understand this concept, we have to pay attention to certain points. To start off with, we must remember that the asymptote = h, and that is where it will go along the x line. While solving the y intercept, we must make sure that we use the change of base to figure out y. Everything else should be pretty clear. Thanks for watching.
SP# 3: Unit I Concept 1: Graphing exponential functions and identifying x-intercept, y-intercept, asymptotes, domain, and range
The viewer needs to pay attention to certain points in order to fully understand this concept. For one, there can not be a x intercept if there is a negative because how can we take the natural log of a negative? Also, we must remember from previous chapters that x=0, and y=0, and we can find the x and y intercepts. Also, the domain will usually be all real numbers, meaning -infinity to +infinity. Lastly, we should remember that when looking for the asymptote, y=k. THANK YOU.
Sunday, October 20, 2013
SV#3: Unit H Concept 7 - Finding Logs Given Approximations
Pay close attention to a couple different things in this video. First, notice how the "4" is used replaced to one because log base 4 of 4 is 1. Also, the 5 is being subtracted because it's the denominator in the original problem. Also, the 2(k) is there because 9 breaks into two 3's. Thanks for watching. :)
Tuesday, October 8, 2013
SV#2: Unit G Concepts 1-7 - Finding all parts and graphing a rational function
This problem is about asymptotes. In this problem, because the number on top is 1 degree bigger, it is a slant asymptote. Here, I will show you how to find the Vertical asymptote, holes, domain, x & y intercept, and how to graph. :) enjoy.
Pay special attention to the y=mx+b equation because that will lead our slant. Also, make sure to plug in the equation to your graphing calculator when finding the vertical asymptotes.
Thank you.
Pay special attention to the y=mx+b equation because that will lead our slant. Also, make sure to plug in the equation to your graphing calculator when finding the vertical asymptotes.
Thank you.
Monday, September 30, 2013
SV#1: Unit F Concept 10 - Finding all real and imaginary zeroes of a polynomial
This problem is about finding real and complex numbers. Here, we find out how to find the zeros of an equation. The zeros can be real or imaginary, here's an example of imaginary zeros.
Pay special attention to how I plug in the zeros to the calculator. Also, pay special attention to my final answer because it can be written 2 different ways. Other than that, I explain every step of the way. :)
THANK YOU FOR WATCHING/LISTENING FOR 14 MINUTES.
Pay special attention to how I plug in the zeros to the calculator. Also, pay special attention to my final answer because it can be written 2 different ways. Other than that, I explain every step of the way. :)
THANK YOU FOR WATCHING/LISTENING FOR 14 MINUTES.
Tuesday, September 17, 2013
WPP#4: Unit E Concept 3 - Maximizing Area
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SP#2: Unit E Concept 7 - Graphing a polynomial and identifying all key parts
This problem is about graphing polynomails, including the x and y intercept (with multiplicities), end behavior.
To begin with, I factored out the equation above which lead me to my zeros. My original equation was to the 4th power which means I need 4 zeros. When i factored out the equation, I ended up with 4 zeros. Also, since the original equation started with "x^4" (both positive = even positive) the graph will be going up whether it's going to infnity or negative infinity. We find the y-intercept by setting "x" to 0 in the original equation. After all that, we plot all the points given, and make sure the graph is going upwards both ways. :)
Wednesday, September 11, 2013
SP#1: Unit E Concept 1 - Graphing a quadratic and identifying all key parts
This problem is about identifying x-intercepts, y intercepts, the vertex, the axis of quadratics and how to graph it. Here's an example where I used my own example.
To begin with, my problem was f(x)=2x^2+4x-16. I subtracted 16 on both sides which gave me 2x^2+4x=16. I then took out the coeficiant which is 2 and added it to the other side as well, and it gave me 2(x^2+2x)=16+2. After, I divided "b" by 2 which is 1 and squared it which is 1 and added 1 to both sides. I ended up with 2(x^2+2x+1)= 16+2(1). KEEP IN MIND THAT "2(x^2+2x+1)" FACTORS OUT. 2(x+1)^2=18. Subtract 18 over and we have the parent function equation which is 2(x+1)^2-18. The vertex is a minimum and is (-1,-18). To find the y intercept, we would need to set "x"=to 0 in the original equation which makes it (0,-16). The axis is "x=-1" because of the vertex. Now to find the x intercepts, we just need to solve, "2(x+1)^2=18" :)
Monday, September 9, 2013
WPP#3: Unit E Concept 2 - Path of Soccer Ball
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Friday, September 6, 2013
WPP#2: Unit A Concept 7 - Profit, Revenue, Cost
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Thursday, September 5, 2013
WPP#1: Unit A Concept 6 - Linear Models
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